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(5x+4)(-2x+2)=0
We multiply parentheses ..
(-10x^2+10x-8x+8)=0
We get rid of parentheses
-10x^2+10x-8x+8=0
We add all the numbers together, and all the variables
-10x^2+2x+8=0
a = -10; b = 2; c = +8;
Δ = b2-4ac
Δ = 22-4·(-10)·8
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-18}{2*-10}=\frac{-20}{-20} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+18}{2*-10}=\frac{16}{-20} =-4/5 $
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