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(5x+4)(6x-1)=80
We move all terms to the left:
(5x+4)(6x-1)-(80)=0
We multiply parentheses ..
(+30x^2-5x+24x-4)-80=0
We get rid of parentheses
30x^2-5x+24x-4-80=0
We add all the numbers together, and all the variables
30x^2+19x-84=0
a = 30; b = 19; c = -84;
Δ = b2-4ac
Δ = 192-4·30·(-84)
Δ = 10441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{10441}}{2*30}=\frac{-19-\sqrt{10441}}{60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{10441}}{2*30}=\frac{-19+\sqrt{10441}}{60} $
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