4(2y-3)=7(y+4)

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Solution for 4(2y-3)=7(y+4) equation: 



4(2y-3)=7(y+4)

We move all terms to the left:

4(2y-3)-(7(y+4))=0

We multiply parentheses

8y-(7(y+4))-12=0



We calculate terms in parentheses: -(7(y+4)), so:

7(y+4)

We multiply parentheses

7y+28

Back to the equation:

-(7y+28)



We get rid of parentheses

8y-7y-28-12=0

We add all the numbers together, and all the variables

y-40=0

We move all terms containing y to the left, all other terms to the right

y=40

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