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(5x+4)(5x-6)=0
We multiply parentheses ..
(+25x^2-30x+20x-24)=0
We get rid of parentheses
25x^2-30x+20x-24=0
We add all the numbers together, and all the variables
25x^2-10x-24=0
a = 25; b = -10; c = -24;
Δ = b2-4ac
Δ = -102-4·25·(-24)
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-50}{2*25}=\frac{-40}{50} =-4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+50}{2*25}=\frac{60}{50} =1+1/5 $
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