2(x-4)+8x=-2(4x-5)+12

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Solution for 2(x-4)+8x=-2(4x-5)+12 equation: 



2(x-4)+8x=-2(4x-5)+12

We move all terms to the left:

2(x-4)+8x-(-2(4x-5)+12)=0

We add all the numbers together, and all the variables

8x+2(x-4)-(-2(4x-5)+12)=0

We multiply parentheses

8x+2x-(-2(4x-5)+12)-8=0



We calculate terms in parentheses: -(-2(4x-5)+12), so:

-2(4x-5)+12

We multiply parentheses

-8x+10+12

We add all the numbers together, and all the variables

-8x+22

Back to the equation:

-(-8x+22)



We add all the numbers together, and all the variables

10x-(-8x+22)-8=0

We get rid of parentheses

10x+8x-22-8=0

We add all the numbers together, and all the variables

18x-30=0

We move all terms containing x to the left, all other terms to the right

18x=30

x=30/18

x=1+2/3

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