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(5x+2)/4x=15
We move all terms to the left:
(5x+2)/4x-(15)=0
Domain of the equation: 4x!=0We multiply all the terms by the denominator
x!=0/4
x!=0
x∈R
(5x+2)-15*4x=0
Wy multiply elements
(5x+2)-60x=0
We get rid of parentheses
5x-60x+2=0
We add all the numbers together, and all the variables
-55x+2=0
We move all terms containing x to the left, all other terms to the right
-55x=-2
x=-2/-55
x=2/55
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