(2x+5)+(3x+11)=(4x+10)+(7x+6)

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Solution for (2x+5)+(3x+11)=(4x+10)+(7x+6) equation: 



(2x+5)+(3x+11)=(4x+10)+(7x+6)

We move all terms to the left:

(2x+5)+(3x+11)-((4x+10)+(7x+6))=0

We get rid of parentheses

2x+3x-((4x+10)+(7x+6))+5+11=0



We calculate terms in parentheses: -((4x+10)+(7x+6)), so:

(4x+10)+(7x+6)

We get rid of parentheses

4x+7x+10+6

We add all the numbers together, and all the variables

11x+16

Back to the equation:

-(11x+16)



We add all the numbers together, and all the variables

5x-(11x+16)+16=0

We get rid of parentheses

5x-11x-16+16=0

We add all the numbers together, and all the variables

-6x=0

x=0/-6

x=0

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