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(5x+2)(5x-2)=180
We move all terms to the left:
(5x+2)(5x-2)-(180)=0
We use the square of the difference formula
25x^2-4-180=0
We add all the numbers together, and all the variables
25x^2-184=0
a = 25; b = 0; c = -184;
Δ = b2-4ac
Δ = 02-4·25·(-184)
Δ = 18400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18400}=\sqrt{400*46}=\sqrt{400}*\sqrt{46}=20\sqrt{46}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{46}}{2*25}=\frac{0-20\sqrt{46}}{50} =-\frac{20\sqrt{46}}{50} =-\frac{2\sqrt{46}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{46}}{2*25}=\frac{0+20\sqrt{46}}{50} =\frac{20\sqrt{46}}{50} =\frac{2\sqrt{46}}{5} $
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