6z+4(z-2)=2(5z-4)

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Solution for 6z+4(z-2)=2(5z-4) equation: 



6z+4(z-2)=2(5z-4)

We move all terms to the left:

6z+4(z-2)-(2(5z-4))=0

We multiply parentheses

6z+4z-(2(5z-4))-8=0



We calculate terms in parentheses: -(2(5z-4)), so:

2(5z-4)

We multiply parentheses

10z-8

Back to the equation:

-(10z-8)



We add all the numbers together, and all the variables

10z-(10z-8)-8=0

We get rid of parentheses

10z-10z+8-8=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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