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(5x+2)(3x+7)=0
We multiply parentheses ..
(+15x^2+35x+6x+14)=0
We get rid of parentheses
15x^2+35x+6x+14=0
We add all the numbers together, and all the variables
15x^2+41x+14=0
a = 15; b = 41; c = +14;
Δ = b2-4ac
Δ = 412-4·15·14
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-29}{2*15}=\frac{-70}{30} =-2+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+29}{2*15}=\frac{-12}{30} =-2/5 $
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