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1/2p-3/5=3+1/5p
We move all terms to the left:
1/2p-3/5-(3+1/5p)=0
Domain of the equation: 2p!=0
p!=0/2
p!=0
p∈R
Domain of the equation: 5p)!=0We add all the numbers together, and all the variables
p!=0/1
p!=0
p∈R
1/2p-(1/5p+3)-3/5=0
We get rid of parentheses
1/2p-1/5p-3-3/5=0
We calculate fractions
125p/250p^2+(-2p)/250p^2+(-6p)/250p^2-3=0
We multiply all the terms by the denominator
125p+(-2p)+(-6p)-3*250p^2=0
Wy multiply elements
-750p^2+125p+(-2p)+(-6p)=0
We get rid of parentheses
-750p^2+125p-2p-6p=0
We add all the numbers together, and all the variables
-750p^2+117p=0
a = -750; b = 117; c = 0;
Δ = b2-4ac
Δ = 1172-4·(-750)·0
Δ = 13689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13689}=117$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(117)-117}{2*-750}=\frac{-234}{-1500} =39/250 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(117)+117}{2*-750}=\frac{0}{-1500} =0 $
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