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(5x+12)+(3x+13)=(12x-3)
We move all terms to the left:
(5x+12)+(3x+13)-((12x-3))=0
We get rid of parentheses
5x+3x-((12x-3))+12+13=0
We calculate terms in parentheses: -((12x-3)), so:We add all the numbers together, and all the variables
(12x-3)
We get rid of parentheses
12x-3
Back to the equation:
-(12x-3)
8x-(12x-3)+25=0
We get rid of parentheses
8x-12x+3+25=0
We add all the numbers together, and all the variables
-4x+28=0
We move all terms containing x to the left, all other terms to the right
-4x=-28
x=-28/-4
x=+7
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