4(r-2)=3(2r-12)

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Solution for 4(r-2)=3(2r-12) equation: 



4(r-2)=3(2r-12)

We move all terms to the left:

4(r-2)-(3(2r-12))=0

We multiply parentheses

4r-(3(2r-12))-8=0



We calculate terms in parentheses: -(3(2r-12)), so:

3(2r-12)

We multiply parentheses

6r-36

Back to the equation:

-(6r-36)



We get rid of parentheses

4r-6r+36-8=0

We add all the numbers together, and all the variables

-2r+28=0

We move all terms containing r to the left, all other terms to the right

-2r=-28

r=-28/-2

r=+14

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