(5x+1)7=(2x-5)/4

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Solution for (5x+1)7=(2x-5)/4 equation:



(5x+1)7=(2x-5)/4
We move all terms to the left:
(5x+1)7-((2x-5)/4)=0
We multiply parentheses
35x-((2x-5)/4)+7=0
We multiply all the terms by the denominator
35x*4)-((2x-5)+7*4)=0
We add all the numbers together, and all the variables
35x*4)-((2x-5)=0
Wy multiply elements
140x^2=0
a = 140; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·140·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{280}=0$

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