9(b-4)-7b=5(3b-3)

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Solution for 9(b-4)-7b=5(3b-3) equation: 



9(b-4)-7b=5(3b-3)

We move all terms to the left:

9(b-4)-7b-(5(3b-3))=0

We add all the numbers together, and all the variables

-7b+9(b-4)-(5(3b-3))=0

We multiply parentheses

-7b+9b-(5(3b-3))-36=0



We calculate terms in parentheses: -(5(3b-3)), so:

5(3b-3)

We multiply parentheses

15b-15

Back to the equation:

-(15b-15)



We add all the numbers together, and all the variables

2b-(15b-15)-36=0

We get rid of parentheses

2b-15b+15-36=0

We add all the numbers together, and all the variables

-13b-21=0

We move all terms containing b to the left, all other terms to the right

-13b=21

b=21/-13

b=-1+8/13

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