(5x+1)+(3x+11)=(12x-20)

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Solution for (5x+1)+(3x+11)=(12x-20) equation: 



(5x+1)+(3x+11)=(12x-20)

We move all terms to the left:

(5x+1)+(3x+11)-((12x-20))=0

We get rid of parentheses

5x+3x-((12x-20))+1+11=0



We calculate terms in parentheses: -((12x-20)), so:

(12x-20)

We get rid of parentheses

12x-20

Back to the equation:

-(12x-20)



We add all the numbers together, and all the variables

8x-(12x-20)+12=0

We get rid of parentheses

8x-12x+20+12=0

We add all the numbers together, and all the variables

-4x+32=0

We move all terms containing x to the left, all other terms to the right

-4x=-32

x=-32/-4

x=+8

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