F(x)=1x2-4x-12

Solution for F(x)=1x2-4x-12 equation:

(F)=1F^2-4F-12

We move all terms to the left:

(F)-(1F^2-4F-12)=0

We get rid of parentheses

-1F^2+F+4F+12=0

We add all the numbers together, and all the variables

-1F^2+5F+12=0

a = -1; b = 5; c = +12;
Δ = b2-4ac
Δ = 52-4·(-1)·12
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{73}}{2*-1}=\frac{-5-\sqrt{73}}{-2}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{73}}{2*-1}=\frac{-5+\sqrt{73}}{-2}
$