(5x+1)(3x+7)=0

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Solution for (5x+1)(3x+7)=0 equation:



(5x+1)(3x+7)=0
We multiply parentheses ..
(+15x^2+35x+3x+7)=0
We get rid of parentheses
15x^2+35x+3x+7=0
We add all the numbers together, and all the variables
15x^2+38x+7=0
a = 15; b = 38; c = +7;
Δ = b2-4ac
Δ = 382-4·15·7
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-32}{2*15}=\frac{-70}{30} =-2+1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+32}{2*15}=\frac{-6}{30} =-1/5 $

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