5(6y-1)+15=19-(5y-3)

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Solution for 5(6y-1)+15=19-(5y-3) equation: 



5(6y-1)+15=19-(5y-3)

We move all terms to the left:

5(6y-1)+15-(19-(5y-3))=0

We multiply parentheses

30y-(19-(5y-3))-5+15=0



We calculate terms in parentheses: -(19-(5y-3)), so:

19-(5y-3)

determiningTheFunctionDomain
-(5y-3)+19

We get rid of parentheses

-5y+3+19

We add all the numbers together, and all the variables

-5y+22

Back to the equation:

-(-5y+22)



We add all the numbers together, and all the variables

30y-(-5y+22)+10=0

We get rid of parentheses

30y+5y-22+10=0

We add all the numbers together, and all the variables

35y-12=0

We move all terms containing y to the left, all other terms to the right

35y=12

y=12/35

y=12/35

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