(5n)2=25n2

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Solution for (5n)2=25n2 equation:



(5n)2=25n^2
We move all terms to the left:
(5n)2-(25n^2)=0
determiningTheFunctionDomain -25n^2+5n2=0
We add all the numbers together, and all the variables
-20n^2=0
a = -20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-20)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{-40}=0$

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