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6(0.25x-2)=9/6x-12
We move all terms to the left:
6(0.25x-2)-(9/6x-12)=0
Domain of the equation: 6x-12)!=0We multiply parentheses
x∈R
0x-(9/6x-12)-12=0
We get rid of parentheses
0x-9/6x+12-12=0
We multiply all the terms by the denominator
0x*6x+12*6x-12*6x-9=0
Wy multiply elements
0x^2+72x-72x-9=0
We add all the numbers together, and all the variables
x^2-9=0
a = 1; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·1·(-9)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*1}=\frac{-6}{2} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*1}=\frac{6}{2} =3 $
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