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(5d+9)(5d-9)=0
We use the square of the difference formula
25d^2-81=0
a = 25; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·25·(-81)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-90}{2*25}=\frac{-90}{50} =-1+4/5 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+90}{2*25}=\frac{90}{50} =1+4/5 $
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