4(y+1)+y=3(y-1)+3

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Solution for 4(y+1)+y=3(y-1)+3 equation: 



4(y+1)+y=3(y-1)+3

We move all terms to the left:

4(y+1)+y-(3(y-1)+3)=0

We add all the numbers together, and all the variables

y+4(y+1)-(3(y-1)+3)=0

We multiply parentheses

y+4y-(3(y-1)+3)+4=0



We calculate terms in parentheses: -(3(y-1)+3), so:

3(y-1)+3

We multiply parentheses

3y-3+3

We add all the numbers together, and all the variables

3y

Back to the equation:

-(3y)



We add all the numbers together, and all the variables

2y+4=0

We move all terms containing y to the left, all other terms to the right

2y=-4

y=-4/2

y=-2

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