(5c+2)-2c=3(2c+3)+7

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Solution for (5c+2)-2c=3(2c+3)+7 equation: 



(5c+2)-2c=3(2c+3)+7

We move all terms to the left:

(5c+2)-2c-(3(2c+3)+7)=0

We add all the numbers together, and all the variables

-2c+(5c+2)-(3(2c+3)+7)=0

We get rid of parentheses

-2c+5c-(3(2c+3)+7)+2=0



We calculate terms in parentheses: -(3(2c+3)+7), so:

3(2c+3)+7

We multiply parentheses

6c+9+7

We add all the numbers together, and all the variables

6c+16

Back to the equation:

-(6c+16)



We add all the numbers together, and all the variables

3c-(6c+16)+2=0

We get rid of parentheses

3c-6c-16+2=0

We add all the numbers together, and all the variables

-3c-14=0

We move all terms containing c to the left, all other terms to the right

-3c=14

c=14/-3

c=-4+2/3

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