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2(x-4)=5-3(x+1)
We move all terms to the left:
2(x-4)-(5-3(x+1))=0
We multiply parentheses
2x-(5-3(x+1))-8=0
We calculate terms in parentheses: -(5-3(x+1)), so:We get rid of parentheses
5-3(x+1)
determiningTheFunctionDomain -3(x+1)+5
We multiply parentheses
-3x-3+5
We add all the numbers together, and all the variables
-3x+2
Back to the equation:
-(-3x+2)
2x+3x-2-8=0
We add all the numbers together, and all the variables
5x-10=0
We move all terms containing x to the left, all other terms to the right
5x=10
x=10/5
x=2
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