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(5a/4)-(a/3)=(11/2)
We move all terms to the left:
(5a/4)-(a/3)-((11/2))=0
We add all the numbers together, and all the variables
(+5a/4)-(+a/3)-((+11/2))=0
We get rid of parentheses
5a/4-a/3-((+11/2))=0
We calculate fractions
(-16a^2)/()+60a^2/()+()/()=0
We add all the numbers together, and all the variables
(-16a^2)/()+60a^2/()+1=0
We multiply all the terms by the denominator
(-16a^2)+60a^2+1*()=0
We add all the numbers together, and all the variables
60a^2+(-16a^2)=0
We get rid of parentheses
60a^2-16a^2=0
We add all the numbers together, and all the variables
44a^2=0
a = 44; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·44·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$a=\frac{-b}{2a}=\frac{0}{88}=0$
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