(50/8)f=10

Solution for (50/8)f=10 equation:

(50/8)f=10

We move all terms to the left:

(50/8)f-(10)=0


Domain of the equation: 8)f!=0

f!=0/1

f!=0

f∈R


We add all the numbers together, and all the variables

(+50/8)f-10=0

We multiply parentheses

50f^2-10=0

a = 50; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·50·(-10)
Δ = 2000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2000}=\sqrt{400*5}=\sqrt{400}*\sqrt{5}=20\sqrt{5}$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{5}}{2*50}=\frac{0-20\sqrt{5}}{100}
=-\frac{20\sqrt{5}}{100}
=-\frac{\sqrt{5}}{5}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{5}}{2*50}=\frac{0+20\sqrt{5}}{100}
=\frac{20\sqrt{5}}{100}
=\frac{\sqrt{5}}{5}
$