(62/8)f=10

Solution for (62/8)f=10 equation:

(62/8)f=10

We move all terms to the left:

(62/8)f-(10)=0


Domain of the equation: 8)f!=0

f!=0/1

f!=0

f∈R


We add all the numbers together, and all the variables

(+62/8)f-10=0

We multiply parentheses

62f^2-10=0

a = 62; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·62·(-10)
Δ = 2480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2480}=\sqrt{16*155}=\sqrt{16}*\sqrt{155}=4\sqrt{155}$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{155}}{2*62}=\frac{0-4\sqrt{155}}{124}
=-\frac{4\sqrt{155}}{124}
=-\frac{\sqrt{155}}{31}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{155}}{2*62}=\frac{0+4\sqrt{155}}{124}
=\frac{4\sqrt{155}}{124}
=\frac{\sqrt{155}}{31}
$