(50+2x)(30+2x)=2204

Solution for (50+2x)(30+2x)=2204 equation:

(50+2x)(30+2x)=2204

We move all terms to the left:

(50+2x)(30+2x)-(2204)=0

We add all the numbers together, and all the variables

(2x+50)(2x+30)-2204=0

We multiply parentheses ..

(+4x^2+60x+100x+1500)-2204=0

We get rid of parentheses

4x^2+60x+100x+1500-2204=0

We add all the numbers together, and all the variables

4x^2+160x-704=0

a = 4; b = 160; c = -704;
Δ = b2-4ac
Δ = 1602-4·4·(-704)
Δ = 36864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36864}=192$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-192}{2*4}=\frac{-352}{8}
=-44
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+192}{2*4}=\frac{32}{8}
=4
$