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(50+2x)(30+2x)=704
We move all terms to the left:
(50+2x)(30+2x)-(704)=0
We add all the numbers together, and all the variables
(2x+50)(2x+30)-704=0
We multiply parentheses ..
(+4x^2+60x+100x+1500)-704=0
We get rid of parentheses
4x^2+60x+100x+1500-704=0
We add all the numbers together, and all the variables
4x^2+160x+796=0
a = 4; b = 160; c = +796;
Δ = b2-4ac
Δ = 1602-4·4·796
Δ = 12864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12864}=\sqrt{64*201}=\sqrt{64}*\sqrt{201}=8\sqrt{201}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-8\sqrt{201}}{2*4}=\frac{-160-8\sqrt{201}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+8\sqrt{201}}{2*4}=\frac{-160+8\sqrt{201}}{8} $
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