(5/u+3)=(-3/2u+6)+2

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Solution for (5/u+3)=(-3/2u+6)+2 equation:



(5/u+3)=(-3/2u+6)+2
We move all terms to the left:
(5/u+3)-((-3/2u+6)+2)=0
Domain of the equation: u+3)!=0
u∈R
Domain of the equation: 2u+6)+2)!=0
u∈R
We get rid of parentheses
5/u-((-3/2u+6)+2)+3=0
We calculate fractions
10u/2u^2+(-((-3*u)/2u^2+3=0
We add all the numbers together, and all the variables
10u/2u^2+(-((-3u)/2u^2+3=0
We calculate fractions
We do not support eupression: u^4

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