(5/9)c+32=68

Solution for (5/9)c+32=68 equation:

(5/9)c+32=68

We move all terms to the left:

(5/9)c+32-(68)=0


Domain of the equation: 9)c!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

(+5/9)c+32-68=0

We add all the numbers together, and all the variables

(+5/9)c-36=0

We multiply parentheses

5c^2-36=0

a = 5; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·5·(-36)
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{5}}{2*5}=\frac{0-12\sqrt{5}}{10}
=-\frac{12\sqrt{5}}{10}
=-\frac{6\sqrt{5}}{5}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{5}}{2*5}=\frac{0+12\sqrt{5}}{10}
=\frac{12\sqrt{5}}{10}
=\frac{6\sqrt{5}}{5}
$