(2/3)*1+(2/3)*n=-0.5n

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Solution for (2/3)*1+(2/3)*n=-0.5n equation: 



(2/3)*1+(2/3)*n=-0.5n

We move all terms to the left:

(2/3)*1+(2/3)*n-(-0.5n)=0



Domain of the equation: 3)*n!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

(+2/3)*n-(-0.5n)+(+2/3)*1=0

We multiply parentheses

2n^2-(-0.5n)+(+2/3)*1=0

We get rid of parentheses

2n^2+0.5n+(+2/3)*1=0

We multiply all the terms by the denominator


2n^2*3)*1+(0.5n)*3)*1+(+2=0

We add all the numbers together, and all the variables

2n^2*3)*1+(+0.5n)*3)*1+(+2=0

Wy multiply elements

6n^4+0.5n)*3)*1+(+2=0

We do not support enpression: n^4

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