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(5/6)f-(3/4)f+(3/4)=(1/2)
We move all terms to the left:
(5/6)f-(3/4)f+(3/4)-((1/2))=0
Domain of the equation: 6)f!=0
f!=0/1
f!=0
f∈R
Domain of the equation: 4)f!=0We add all the numbers together, and all the variables
f!=0/1
f!=0
f∈R
(+5/6)f-(+3/4)f+(+3/4)-((+1/2))=0
We multiply parentheses
5f^2-3f^2+(+3/4)-((+1/2))=0
We get rid of parentheses
5f^2-3f^2+3/4-((+1/2))=0
We calculate fractions
5f^2-3f^2+()/()+()/()=0
We add all the numbers together, and all the variables
2f^2+2=0
a = 2; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·2·2
Δ = -16
Delta is less than zero, so there is no solution for the equation
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