(5/2y)+(6/2y)=11

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Solution for (5/2y)+(6/2y)=11 equation: 



(5/2y)+(6/2y)=11

We move all terms to the left:

(5/2y)+(6/2y)-(11)=0



Domain of the equation: 2y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+5/2y)+(+6/2y)-11=0

We get rid of parentheses

5/2y+6/2y-11=0

We multiply all the terms by the denominator


-11*2y+5+6=0

We add all the numbers together, and all the variables

-11*2y+11=0

Wy multiply elements

-22y+11=0

We move all terms containing y to the left, all other terms to the right

-22y=-11

y=-11/-22

y=1/2

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