(7x+2)18=(6x+3)20

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Solution for (7x+2)18=(6x+3)20 equation: 



(7x+2)18=(6x+3)20

We move all terms to the left:

(7x+2)18-((6x+3)20)=0

We multiply parentheses

126x-((6x+3)20)+36=0



We calculate terms in parentheses: -((6x+3)20), so:

(6x+3)20

We multiply parentheses

120x+60

Back to the equation:

-(120x+60)



We get rid of parentheses

126x-120x-60+36=0

We add all the numbers together, and all the variables

6x-24=0

We move all terms containing x to the left, all other terms to the right

6x=24

x=24/6

x=4

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