(5/2t)-t=3+(3/2t)

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Solution for (5/2t)-t=3+(3/2t) equation: 



(5/2t)-t=3+(3/2t)

We move all terms to the left:

(5/2t)-t-(3+(3/2t))=0



Domain of the equation: 2t)!=0

t!=0/1

t!=0

t∈R





Domain of the equation: 2t))!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

(+5/2t)-t-(3+(+3/2t))=0

We add all the numbers together, and all the variables

-1t+(+5/2t)-(3+(+3/2t))=0

We get rid of parentheses

-1t+5/2t-(3+(+3/2t))=0

We calculate fractions


-1t+10t/4t^2+(-(3+(+3*2t)/4t^2=0

We multiply all the terms by the denominator


-1t*4t^2+10t+(-(3+(+3*2t)=0



We calculate terms in parentheses: +(-(3+(+3*2t), so:

-(3+(+3*2t



We add all the numbers together, and all the variables

10t-1t*4t^2+(-(3+(+3*2t)=0

Wy multiply elements

-4t^3+10t+(-(3+(+3*2t)=0



We calculate terms in parentheses: +(-(3+(+3*2t), so:

-(3+(+3*2t



We do not support etpression: t^3

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