1/7z+8=-6/7z

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Solution for 1/7z+8=-6/7z equation: 



1/7z+8=-6/7z

We move all terms to the left:

1/7z+8-(-6/7z)=0



Domain of the equation: 7z!=0

z!=0/7

z!=0

z∈R





Domain of the equation: 7z)!=0

z!=0/1

z!=0

z∈R



We get rid of parentheses

1/7z+6/7z+8=0

We multiply all the terms by the denominator


8*7z+1+6=0

We add all the numbers together, and all the variables

8*7z+7=0

Wy multiply elements

56z+7=0

We move all terms containing z to the left, all other terms to the right

56z=-7

z=-7/56

z=-1/8

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