(5/2p)+(2/p)=3/2

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Solution for (5/2p)+(2/p)=3/2 equation: 


D( p )

p = 0

p = 0

p = 0

p in (-oo:0) U (0:+oo)

(5/2)*p+2/p = 3/2 // - 3/2

(5/2)*p+2/p-(3/2) = 0

(5/2)*p+2/p-3/2 = 0

5/2*p^1+2*p^-1-3/2*p^0 = 0

(5/2*p^2-3/2*p^1+2*p^0)/(p^1) = 0 // * p^2

p^1*(5/2*p^2-3/2*p^1+2*p^0) = 0

p^1

(5/2)*p^2+(-3/2)*p+2 = 0

(5/2)*p^2+(-3/2)*p+2 = 0

DELTA = (-3/2)^2-(2*4*(5/2))

DELTA = -71/4

DELTA < 0

p in { } 

p belongs to the empty set

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