(1/x)+(1/x+1)=1/x+2

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Solution for (1/x)+(1/x+1)=1/x+2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+1/x+1 = 1/x+2 // - 1/x+2

1/x+1/x-(1/x)-2+1 = 0

1/x+1/x-x^-1-2+1 = 0

1*x^-1 = 1 // : 1

x^-1 = 1

-1 < 0

1/(x^1) = 1 // * x^1

1 = 1*x^1 // : 1

1 = x^1

x = 1

x = 1

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