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(5/(x+4))+(8/(2x+8)=11
We move all terms to the left:
(5/(x+4))+(8/(2x+8)-(11)=0
Domain of the equation: (x+4))!=0
x∈R
Domain of the equation: (2x+8)-11!=0We calculate fractions
We move all terms containing x to the left, all other terms to the right
(2x+8)!=11
x∈R
((5*(2x+8)-11)/((x+4))*2x+(8x+32)/((x+4))*2x=0
We can not solve this equation
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