((6x+5)/3)+((2x-3)/9)=-12

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Solution for ((6x+5)/3)+((2x-3)/9)=-12 equation: 



((6x+5)/3)+((2x-3)/9)=-12

We move all terms to the left:

((6x+5)/3)+((2x-3)/9)-(-12)=0

We add all the numbers together, and all the variables

((6x+5)/3)+((2x-3)/9)+12=0

We calculate fractions


(54x+45)/()+(6x-9)/()+12=0

We multiply all the terms by the denominator


(54x+45)+(6x-9)+12*()=0

We add all the numbers together, and all the variables

(54x+45)+(6x-9)=0

We get rid of parentheses

54x+6x+45-9=0

We add all the numbers together, and all the variables

60x+36=0

We move all terms containing x to the left, all other terms to the right

60x=-36

x=-36/60

x=-3/5

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