(5-7x)(2+4x)=-8/7

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Solution for (5-7x)(2+4x)=-8/7 equation: 



(5-7x)(2+4x)=-8/7

We move all terms to the left:

(5-7x)(2+4x)-(-8/7)=0

We add all the numbers together, and all the variables

(-7x+5)(4x+2)-(-8/7)=0

We get rid of parentheses

(-7x+5)(4x+2)+8/7=0

We multiply parentheses ..

(-28x^2-14x+20x+10)+8/7=0

We multiply all the terms by the denominator


((-28x^2-14x+20x+10))*7+8=0

We move all terms containing x to the left, all other terms to the right

((-28x^2-14x+20x+10))*7=-8

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