(2x-10)*(-5x+18)=0

Solution for (2x-10)*(-5x+18)=0 equation:

(2x-10)(-5x+18)=0

We multiply parentheses ..

(-10x^2+36x+50x-180)=0

We get rid of parentheses

-10x^2+36x+50x-180=0

We add all the numbers together, and all the variables

-10x^2+86x-180=0

a = -10; b = 86; c = -180;
Δ = b2-4ac
Δ = 862-4·(-10)·(-180)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(86)-14}{2*-10}=\frac{-100}{-20}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(86)+14}{2*-10}=\frac{-72}{-20}
=3+3/5
$