(5-6x)(5-6x)+16=(12x-11)(3x+1)

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Solution for (5-6x)(5-6x)+16=(12x-11)(3x+1) equation:



(5-6x)(5-6x)+16=(12x-11)(3x+1)
We move all terms to the left:
(5-6x)(5-6x)+16-((12x-11)(3x+1))=0
We add all the numbers together, and all the variables
(-6x+5)(-6x+5)-((12x-11)(3x+1))+16=0
We multiply parentheses ..
(+36x^2-30x-30x+25)-((12x-11)(3x+1))+16=0
We calculate terms in parentheses: -((12x-11)(3x+1)), so:
(12x-11)(3x+1)
We multiply parentheses ..
(+36x^2+12x-33x-11)
We get rid of parentheses
36x^2+12x-33x-11
We add all the numbers together, and all the variables
36x^2-21x-11
Back to the equation:
-(36x^2-21x-11)
We get rid of parentheses
36x^2-36x^2-30x-30x+21x+25+11+16=0
We add all the numbers together, and all the variables
-39x+52=0
We move all terms containing x to the left, all other terms to the right
-39x=-52
x=-52/-39
x=1+1/3

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