(4x-12)(3x-9)=0

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Solution for (4x-12)(3x-9)=0 equation: 



(4x-12)(3x-9)=0

We multiply parentheses ..

(+12x^2-36x-36x+108)=0

We get rid of parentheses

12x^2-36x-36x+108=0

We add all the numbers together, and all the variables

12x^2-72x+108=0

a = 12; b = -72; c = +108;
Δ = b2-4ac
Δ = -722-4·12·108
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{72}{24}=3$

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