(5-3x)(3+4x)-(7+3x)(1-4x)=-64

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Solution for (5-3x)(3+4x)-(7+3x)(1-4x)=-64 equation: 



(5-3x)(3+4x)-(7+3x)(1-4x)=-64

We move all terms to the left:

(5-3x)(3+4x)-(7+3x)(1-4x)-(-64)=0

We add all the numbers together, and all the variables

(-3x+5)(4x+3)-(3x+7)(-4x+1)-(-64)=0

We add all the numbers together, and all the variables

(-3x+5)(4x+3)-(3x+7)(-4x+1)+64=0

We multiply parentheses ..

(-12x^2-9x+20x+15)-(3x+7)(-4x+1)+64=0

We get rid of parentheses

-12x^2-9x+20x-(3x+7)(-4x+1)+15+64=0

We multiply parentheses ..

-12x^2-(-12x^2+3x-28x+7)-9x+20x+15+64=0

We add all the numbers together, and all the variables

-12x^2-(-12x^2+3x-28x+7)+11x+79=0

We get rid of parentheses

-12x^2+12x^2-3x+28x+11x-7+79=0

We add all the numbers together, and all the variables

36x+72=0

We move all terms containing x to the left, all other terms to the right

36x=-72

x=-72/36

x=-2

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