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(5+2x)(2x-3)=(4x+5)(x-1)
We move all terms to the left:
(5+2x)(2x-3)-((4x+5)(x-1))=0
We add all the numbers together, and all the variables
(2x+5)(2x-3)-((4x+5)(x-1))=0
We multiply parentheses ..
(+4x^2-6x+10x-15)-((4x+5)(x-1))=0
We calculate terms in parentheses: -((4x+5)(x-1)), so:We get rid of parentheses
(4x+5)(x-1)
We multiply parentheses ..
(+4x^2-4x+5x-5)
We get rid of parentheses
4x^2-4x+5x-5
We add all the numbers together, and all the variables
4x^2+x-5
Back to the equation:
-(4x^2+x-5)
4x^2-4x^2-6x+10x-x-15+5=0
We add all the numbers together, and all the variables
3x-10=0
We move all terms containing x to the left, all other terms to the right
3x=10
x=10/3
x=3+1/3
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