(5(2y-3))/3y=3

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Solution for (5(2y-3))/3y=3 equation: 



(5(2y-3))/3y=3

We move all terms to the left:

(5(2y-3))/3y-(3)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



We multiply all the terms by the denominator


(5(2y-3))-3*3y=0



We calculate terms in parentheses: +(5(2y-3)), so:

5(2y-3)

We multiply parentheses

10y-15

Back to the equation:

+(10y-15)



Wy multiply elements

(10y-15)-9y=0

We get rid of parentheses

10y-9y-15=0

We add all the numbers together, and all the variables

y-15=0

We move all terms containing y to the left, all other terms to the right

y=15

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