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3(x+2)=5+2(x-1)
We move all terms to the left:
3(x+2)-(5+2(x-1))=0
We multiply parentheses
3x-(5+2(x-1))+6=0
We calculate terms in parentheses: -(5+2(x-1)), so:We get rid of parentheses
5+2(x-1)
determiningTheFunctionDomain 2(x-1)+5
We multiply parentheses
2x-2+5
We add all the numbers together, and all the variables
2x+3
Back to the equation:
-(2x+3)
3x-2x-3+6=0
We add all the numbers together, and all the variables
x+3=0
We move all terms containing x to the left, all other terms to the right
x=-3
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